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Nov 28, 2021 at 14:14 history edited Mathew Mahindaratne CC BY-SA 4.0
Improved formatting and clarity. Added few tags.
Nov 28, 2021 at 14:10 answer added Mathew Mahindaratne timeline score: 3
Nov 28, 2021 at 10:31 comment added Poutnik By other words, practically, it is possible to achieve saturated solution Br2(l)<=>Br2(g)<=>Br2(aq), but not NO2(g)<=>[NaOH]NO2(aq). NO2 or NaOH will be spent.
Nov 28, 2021 at 9:50 comment added Poutnik @NilayGhosh Well, bromine water is in very majority a true solution, with the equilibrium strongly shifted to the left. For NO2/NaOH, it is the opposite.
Nov 28, 2021 at 9:39 comment added Nilay Ghosh @Poutnik Relevant line of argument: chemistry.stackexchange.com/questions/42696/…
Nov 28, 2021 at 7:46 comment added Poutnik You may find useful these links for text formatting ( not to be applied to titles ): notation , formulas/expressions/equations and upright vs italic
Nov 28, 2021 at 7:05 comment added Poutnik NO2 reacts with NaOH, forming NaNO2 + NaNO3, so solubility does not make sense.
Nov 28, 2021 at 5:58 history asked user510 CC BY-SA 4.0