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Chemistry

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    $\begingroup$ NO2 reacts with NaOH, forming NaNO2 + NaNO3, so solubility does not make sense. $\endgroup$
    – Poutnik
    Commented Nov 28, 2021 at 7:05
  • $\begingroup$ You may find useful these links for text formatting ( not to be applied to titles ): notation , formulas/expressions/equations and upright vs italic $\endgroup$
    – Poutnik
    Commented Nov 28, 2021 at 7:46
  • $\begingroup$ @Poutnik Relevant line of argument: chemistry.stackexchange.com/questions/42696/… $\endgroup$
    – Nilay Ghosh
    Commented Nov 28, 2021 at 9:39
  • $\begingroup$ @NilayGhosh Well, bromine water is in very majority a true solution, with the equilibrium strongly shifted to the left. For NO2/NaOH, it is the opposite. $\endgroup$
    – Poutnik
    Commented Nov 28, 2021 at 9:50
  • $\begingroup$ By other words, practically, it is possible to achieve saturated solution Br2(l)<=>Br2(g)<=>Br2(aq), but not NO2(g)<=>[NaOH]NO2(aq). NO2 or NaOH will be spent. $\endgroup$
    – Poutnik
    Commented Nov 28, 2021 at 10:31