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Chemistry

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    $\begingroup$ The answer depends on whether you use log to base 10 or base e, i.e whether you are taught $I/I_0=10^{-\epsilon c l}$ or $e^{-\epsilon c l}$. As the absorption coefficient is $\epsilon c=0.8 $ (which you can see by looking at units) you can calculate the answer by making $I=I_0/2$ $\endgroup$
    – porphyrin
    Commented Aug 1, 2020 at 16:58