Timeline for Calculating ratio of conjugate base and acid when pH and pKa are given
Current License: CC BY-SA 4.0
11 events
| when toggle format | what | by | license | comment | |
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| May 11, 2020 at 1:31 | history | edited | Mathew Mahindaratne | CC BY-SA 4.0 |
Edited to improve formatting and clarity.
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| May 10, 2020 at 23:30 | comment | added | ACR | Did you read my answer once again? | |
| May 10, 2020 at 22:54 | comment | added | Liz | Sorry for many questions, but I really don't understand. If the question is HCO3-/H2CO3 (CONJUGATE BASE)/(ACID), why is used ACID/CONJUGATE BASE in the resolution? | |
| May 10, 2020 at 22:42 | comment | added | ACR | The acid is H2CO3 and its conjugate base is HCO3- | |
| May 10, 2020 at 22:33 | comment | added | Liz | "What is the ratio between HCO3− and H2CO3" don't mean HCO3-/H2CO3? Can you say which one is the acid? | |
| May 10, 2020 at 22:30 | comment | added | ACR | @Liz, The solution in the white box is correct. See the equations I wrote, with negative sign with log, acid will be in numerator. | |
| May 10, 2020 at 22:15 | comment | added | Liz | I put the image now | |
| May 10, 2020 at 22:12 | comment | added | Liz | Good night. The acid is H2CO3, right? And the conjugats base is HCO3-. In this reaction H2CO3 -> H+ + HCO3- | |
| May 10, 2020 at 21:58 | comment | added | ACR | Students can be further confused by the fact that $p=-log$. That is another headache. | |
| May 10, 2020 at 21:43 | comment | added | MaxW | I wish an image of the text would posted too in such cases. I'm guessing that by far the most probable explanation was that the OP just missed the flip in the log, but it is possible that the book was wrong. | |
| May 10, 2020 at 21:32 | history | answered | ACR | CC BY-SA 4.0 |