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Post Closed as "Not suitable for this site" by Mathew Mahindaratne, Tyberius♦, Mithoron, user55119, Jon Custer
Edited to improve text, formatting of the diagram, and clarity.
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Mathew Mahindaratne
Mathew Mahindaratne
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Optical activity of substituted biphenyl

[why isn't this compound optically active? ] HowHow come the given compound in the diagram is optically inactive? The two rings should be in different planes due to steric hindrance between cooh$\ce{COOH}$ and bromine, right?!. How am I wrong?

why isn't this compound optically active?

Optical activity of biphenyl

[why isn't this compound optically active? ] How come the given compound is optically inactive? The two rings should be in different planes due to steric hindrance between cooh and bromine, right?! How am I wrong?

Optical activity of substituted biphenyl

How come the given compound in the diagram is optically inactive? The two rings should be in different planes due to steric hindrance between $\ce{COOH}$ and bromine. How am I wrong?

why isn't this compound optically active?

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Loveforphysics
Loveforphysics
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Optical activity of biphenyl

[why isn't this compound optically active? ] How come the given compound is optically inactive? The two rings should be in different planes due to steric hindrance between cooh and bromine, right?! How am I wrong?