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Which of the following are identical?

 

2,3‐dihydroxy‐4‐methoxy‐4‐oxobutanoic acid isomers

 
  1. A and B are identical
  2. A and B are diastereomers
  3. A and C are enantiomers
  4. A and B are enantiomers

What I know is that when we rotate a Fisher projection by 180°, then we get identical compounds (I might be wrong). But how to tell if the compounds are enantiomers of each other or not?

For that how to get the same group, i.e. $\ce{-COOH}$ in this case at the top to compare the compounds?

Also, is there any trick to tell that if they are diastereomers, enantiomers or identical by the hydroxyl group positions in Fisher projections?

Which of the following are identical?

 

2,3‐dihydroxy‐4‐methoxy‐4‐oxobutanoic acid isomers

 
  1. A and B are identical
  2. A and B are diastereomers
  3. A and C are enantiomers
  4. A and B are enantiomers

What I know is that when we rotate a Fisher projection by 180°, then we get identical compounds (I might be wrong). But how to tell if the compounds are enantiomers of each other or not?

For that how to get the same group, i.e. $\ce{-COOH}$ in this case at the top to compare the compounds?

Also, is there any trick to tell that if they are diastereomers, enantiomers or identical by the hydroxyl group positions in Fisher projections?

Which of the following are identical?

2,3‐dihydroxy‐4‐methoxy‐4‐oxobutanoic acid isomers

  1. A and B are identical
  2. A and B are diastereomers
  3. A and C are enantiomers
  4. A and B are enantiomers

What I know is that when we rotate a Fisher projection by 180°, then we get identical compounds (I might be wrong). But how to tell if the compounds are enantiomers of each other or not?

For that how to get the same group, i.e. $\ce{-COOH}$ in this case at the top to compare the compounds?

Also, is there any trick to tell that if they are diastereomers, enantiomers or identical by the hydroxyl group positions in Fisher projections?

Redrawn structures with chemfig; OCRed photo; corrected markup, capitalization and punctuation; added compound name
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andselisk ♦
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Which of the following isomers of 2,3‐dihydroxy‐4‐methoxy‐4‐oxobutanoic acid are identical?

enter image description here

Which of the following are identical?

2,3‐dihydroxy‐4‐methoxy‐4‐oxobutanoic acid isomers

  1. A and B are identical
  2. A and B are diastereomers
  3. A and C are enantiomers
  4. A and B are enantiomers

So what iWhat I know is that when we rotate a fisherFisher projection by 180°, then we get identical compounds ( II might be wrong)

 . But how to tell if the compounds are enantiomers of each other or not.?

For that how to get the same group, i.e. -cooh$\ce{-COOH}$ in this case at the top to compare the compounds?

Also, is there any trick to tell that if they are diastereomers, enantiomers or identical by the hydroxyl group positions in fisherFisher projections?

Which of the following are identical?

enter image description here

So what i know is that when we rotate a fisher projection by 180° then we get identical compounds ( I might be wrong)

  But how to tell if the compounds are enantiomers of each other or not.

For that how to get the same group i.e -cooh in this case at the top to compare the compounds

Also is there any trick to tell that if they are diastereomers, enantiomers or identical by the hydroxyl group positions in fisher projections?

Which of the following isomers of 2,3‐dihydroxy‐4‐methoxy‐4‐oxobutanoic acid are identical?

Which of the following are identical?

2,3‐dihydroxy‐4‐methoxy‐4‐oxobutanoic acid isomers

  1. A and B are identical
  2. A and B are diastereomers
  3. A and C are enantiomers
  4. A and B are enantiomers

What I know is that when we rotate a Fisher projection by 180°, then we get identical compounds (I might be wrong). But how to tell if the compounds are enantiomers of each other or not?

For that how to get the same group, i.e. $\ce{-COOH}$ in this case at the top to compare the compounds?

Also, is there any trick to tell that if they are diastereomers, enantiomers or identical by the hydroxyl group positions in Fisher projections?

Post Reopened by andselisk♦
Cropped the pic and changed wordings
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studious
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enter image description hereenter image description here

So what i know is that when we rotate a fisher projection by 180° then we get identical compounds ( I might be wrong)

Going withBut how to tell if the compounds are enantiomers of each other or not.

For that i thinkhow to get the option 1 should be correct butsame group i.e -cooh in this case at the keytop to compare the option 4 is given as correct. How is that so?compounds

Also is there any trick to tell that if they are diastereomers, enantiomers or identical by the hydroxyl group positions in fisher projections?

enter image description here

So what i know is that when we rotate a fisher projection by 180° then we get identical compounds

Going with that i think the option 1 should be correct but in the key the option 4 is given as correct. How is that so?

Also is there any trick to tell that if they are diastereomers, enantiomers or identical?

enter image description here

So what i know is that when we rotate a fisher projection by 180° then we get identical compounds ( I might be wrong)

But how to tell if the compounds are enantiomers of each other or not.

For that how to get the same group i.e -cooh in this case at the top to compare the compounds

Also is there any trick to tell that if they are diastereomers, enantiomers or identical by the hydroxyl group positions in fisher projections?

Post Closed as "Not suitable for this site" by Todd Minehardt, Mathew Mahindaratne, Poutnik, Buck Thorn♦, Jon Custer
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studious
studious
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