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Chemistry

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    $\begingroup$ You can create two STATIC images of methanol that are non-superimposable mirror images but that does not make methanol optically active. Every conformation has a mirror image, i.e., a racemate, or a plane of symmetry. Both conditions lead to a lack of optical activity. Consider changing classes. $\endgroup$
    – user55119
    Commented Jul 1, 2019 at 13:20
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    $\begingroup$ The -OH group is pretty much free to rotate around. If not for this fact, your teacher would be wrong just once. $\endgroup$
    – Ivan Neretin
    Commented Jul 1, 2019 at 15:39
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    $\begingroup$ Is your teacher an engineer? $\endgroup$
    – electronpusher
    Commented Jul 1, 2019 at 15:47
  • $\begingroup$ Thanks @user55119 for your answer. I however for some reason can't tick your answer because I found it helpful. $\endgroup$
    – zombiesauce
    Commented Jul 3, 2019 at 15:08