Don't know about the energy transfer but from a rough assumption we can calculate the energy amount that actually passed through Earth depending on the mass converted and the distance of the event. The energy absorbed by Earth would be far less than that obviously.
The measured event was two black holes merging with a total mass loss of $3 M_{\odot}$. While the distance for that event was calculated to $1.3*10^9 ly$.
With comparing the total energy released (assuming full conversion of mass to gravitational wave energy) over the released area:
$$
E_{Earth} = \pi r_{Earth}^2*\frac{m_{conv}c^2}{4\pi r_{dist}^2}
$$
$$
E_{Earth} \approx (6378km)^2*\frac{3M_{\odot}*c^2}{4*(1.3*10^9years*c)^2}
$$
$$
E_{Earth} \approx 4.0*10^{13}m^2*\frac{5.7*10^{30}kg}{6.72*10^{33}s^2}
$$
$$
E_{Earth} \approx 3.39 * 10^{10}J
$$
So the maximum amount of energy passing through earth would have been roughly $34 GJ$. That is about the kinetic energy of three Boeing 747 in flight - or neglectable on a planetary scale.
So even IF the total energy would have been absorbed by Earth, the amount would still have been - not much.