You are not logged in. Your edit will be placed in a queue until it is peer reviewed.
We welcome edits that make the post easier to understand and more valuable for readers. Because community members review edits, please try to make the post substantially better than how you found it, for example, by fixing grammar or adding additional resources and hyperlinks.
-
1$\begingroup$ There is a reasonably well-defined mid plane and the Sun is above it and being accelerated back towards it. The thickness isn't really relevant (other than to make SHM a better approximation). $\endgroup$– ProfRobCommented Jun 10 at 19:10
-
2$\begingroup$ Yes "reasonably" well defined. But still the uncertainty in the location of the mid plane is a lot more than a few AU. And there is nothing particularly on or around the mid plane. "Above" is of course conventional, not in any sense absolute. If we choose to view the galaxy from the other size, it would be rotating in the oppose sense and the sun would be below the plane. $\endgroup$– James KCommented Jun 10 at 19:37
-
1$\begingroup$ @ProfRob SHM is not a good approximation at all, except perhaps for orbits that don't move more than a few pc out from the mid plane. $\endgroup$– WalterCommented Jun 12 at 1:44
-
1$\begingroup$ @Walter How so? The epicyclic approximation for near circular orbits is a totally standard bit of galactic dynamics isn't it? The SHM approx is good so long as you can assume the density is constant. Hence as long as the vertical amplitude is less than the vertical scale on which the density varies. galaxiesbook.org/chapters/II-03.-Orbits-in-Disks.html (Sec 10.3.1). Which is what I said. $\endgroup$– ProfRobCommented Jun 12 at 7:10
-
1$\begingroup$ @ProfRob At one scale height you are already making significant errors with SH. For a vertically exponential density $\rho(z)=(\Sigma/2h)\exp(-\zeta)$ with $\zeta=|z|/h$, the potential is $\Phi=2\pi G\Sigma h[\zeta-1+\exp(-\zeta)] = \tfrac12\omega^2z^2[1-\tfrac13\zeta+O(\zeta^2)]$. Thus, the deviation from SH is first not second order and becomes significant early. The force $F=-\omega^2z[1-\tfrac12\zeta+O(\zeta^2)]$ deviates by ~50% from SH by $|z|=h$. At low $|z|$, the ISM layer becomes important, which has a scale height of $\sim 40\,$pc. So, the SH is perhaps okay for $|z|<20\,$pc. $\endgroup$– WalterCommented Jun 19 at 10:33
|
Show 4 more comments
How to Edit
- Correct minor typos or mistakes
- Clarify meaning without changing it
- Add related resources or links
- Always respect the author’s intent
- Don’t use edits to reply to the author
How to Format
-
create code fences with backticks ` or tildes ~
```
like so
``` -
add language identifier to highlight code
```python
def function(foo):
print(foo)
``` - put returns between paragraphs
- for linebreak add 2 spaces at end
- _italic_ or **bold**
- quote by placing > at start of line
- to make links (use https whenever possible)
<https://example.com>
[example](https://example.com)
<a href="https://example.com">example</a> - MathJax equations
$\sin^2 \theta$
How to Tag
A tag is a keyword or label that categorizes your question with other, similar questions. Choose one or more (up to 5) tags that will help answerers to find and interpret your question.
- complete the sentence: my question is about...
- use tags that describe things or concepts that are essential, not incidental to your question
- favor using existing popular tags
- read the descriptions that appear below the tag
If your question is primarily about a topic for which you can't find a tag:
- combine multiple words into single-words with hyphens (e.g. observational-astronomy), up to a maximum of 35 characters
- creating new tags is a privilege; if you can't yet create a tag you need, then post this question without it, then ask the community to create it for you