Timeline for How exactly does Hawking radiation decrease the mass of black holes?
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| Nov 24, 2020 at 4:19 | comment | added | userLTK | @StevenGubkin Yes, the proportions should be equal or very nearly equal. Most of the particles are photons, which are their own anti-particle or neutrinos, which may be their own anti particle, so it's not always relevant, but when relevant, it's equal amounts. Also, I feel I should point, not to you, but in general that anti matter and virtual particles are entirely different things. I've seen people get that mixed up. | |
| Sep 13, 2020 at 2:32 | comment | added | alexchandel | Indeed the "Heisenberg/virtual-particle" explanation is false. Uhruh radiation is a better analogy given the Bogoliubov transformations' use.. But a simplified, accurate explanation of why mass decreases is still missing from this site. | |
| Jul 16, 2019 at 4:35 | comment | added | zibadawa timmy | @JBentley The pair retain the relationship that they combine to have (approximately) zero energy. But there are no "real" particles in the universe that have non-positive energy. Therefore any particle which escapes must have positive energy, and to preserve the relation the infalling one (which disappears from the universe and past the horizon) must have negative energy. So the black hole loses from it's mass-energy in the exchange, every single time. | |
| Apr 26, 2019 at 18:16 | comment | added | JBentley | @FlorinAndrei I got that. I just would like the missing piece for it to make sense :) (obligatory xkcd) | |
| Apr 26, 2019 at 17:53 | comment | added | Florin Andrei | @JBentley It's just a story anyway. | |
| Apr 26, 2019 at 16:52 | comment | added | JBentley | I'm struggling with one part of the intuition - why is the particle which escapes converted to "real" while the one which is captured (and thus doesn't annihilate any more than the escaping one) remains "virtual"? I think the answer needs to address what is meant by real vs virtual. My intuition tells me that the escaping particle and the captured particle are just as real as each other, and thus the black hole may have lost mass/energy allowing one to escape, but it has gained the mass/energy of the captured one, resulting in an overall loss of zero. | |
| Apr 26, 2019 at 12:11 | comment | added | Steven Gubkin | Do you get particles and anti-particles in equal proportion? | |
| Apr 26, 2019 at 5:40 | history | edited | Florin Andrei | CC BY-SA 4.0 |
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| Apr 25, 2019 at 12:49 | comment | added | PM 2Ring | @Marko Also see math.ucr.edu/home/baez/physics/Relativity/BlackHoles/… | |
| Apr 25, 2019 at 11:21 | comment | added | marko-36 | This "pop-sci fairytale", as you called it yourself, is quite a pleasant read, I even laughed. Thanks. But it is this "I dunno magic" I am after: how does the virtual particle get it's real state (besides magic) and how does this contribute to BH evaporation, having that nothing can escape the black hole.. | |
| Apr 25, 2019 at 10:58 | history | edited | Florin Andrei | CC BY-SA 4.0 |
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| Apr 25, 2019 at 10:50 | history | edited | Florin Andrei | CC BY-SA 4.0 |
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| Apr 25, 2019 at 10:36 | history | answered | Florin Andrei | CC BY-SA 4.0 |