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$\begingroup$ This "pop-sci fairytale", as you called it yourself, is quite a pleasant read, I even laughed. Thanks. But it is this "I dunno magic" I am after: how does the virtual particle get it's real state (besides magic) and how does this contribute to BH evaporation, having that nothing can escape the black hole.. $\endgroup$
– marko-36
Commented Apr 25, 2019 at 11:21
3

$\begingroup$ @Marko Also see math.ucr.edu/home/baez/physics/Relativity/BlackHoles/… $\endgroup$
– PM 2Ring
Commented Apr 25, 2019 at 12:49
$\begingroup$ Do you get particles and anti-particles in equal proportion? $\endgroup$
– Steven Gubkin
Commented Apr 26, 2019 at 12:11
2

$\begingroup$ I'm struggling with one part of the intuition - why is the particle which escapes converted to "real" while the one which is captured (and thus doesn't annihilate any more than the escaping one) remains "virtual"? I think the answer needs to address what is meant by real vs virtual. My intuition tells me that the escaping particle and the captured particle are just as real as each other, and thus the black hole may have lost mass/energy allowing one to escape, but it has gained the mass/energy of the captured one, resulting in an overall loss of zero. $\endgroup$
– JBentley
Commented Apr 26, 2019 at 16:52
2

$\begingroup$ Indeed the "Heisenberg/virtual-particle" explanation is false. Uhruh radiation is a better analogy given the Bogoliubov transformations' use.. But a simplified, accurate explanation of why mass decreases is still missing from this site. $\endgroup$
– alexchandel
Commented Sep 13, 2020 at 2:32

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