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  • $\begingroup$ So, if I'm doing my math right, that's about 1.25 W/m^2 at 1 AU. I realize a lot of it's outside the visible spectrum, but it sounds like you'd be able to see with the naked eye it if you got close enough. (Though you might want to stay back on account of the X-rays and use a telescope.) $\endgroup$ Commented Oct 9, 2018 at 0:58