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There are couple of problems. Here is the working form :

#!/bin/bash
function copyFiles {
   arr=( "$@" )
   for i in "${arr[@]}";
      do
          echo "$i"
      done

}

array=("one" "two" "three")
copyFiles "${array[@]}"

• There need to be at least a space between function declaration and {

• You can not use $array, as array is an array not a variable. If you want to get all the values of an array use "${array[@]}"

• In you main function declaration you need arr="$@" as "${array[@]}" will expand to the indexed values separated by spaces, if you use $1 you would get only the first value. To get all the values use arr="$arr[@]}".

There are couple of problems. Here is the working form :

#!/bin/bash
function copyFiles {
   arr=( "$@" )
   for i in "${arr[@]}";
      do
          echo "$i"
      done

}

array=("one" "two" "three")
copyFiles "${array[@]}"

• There need to be at least a space between function declaration and {

• You can not use $array, as array is an array not a variable. If you want to get all the values of an array use "${array[@]}"

• In you main function declaration you need arr="$@" as "${array[@]}" will expand to the indexed values separated by spaces, if you use $1 you would get only the first value. To get all the values use arr="${arr[@]}".

There are couple of problems. Here is the working form :

#!/bin/bash
function copyFiles {
   arr=( "$@" )
   for i in "${arr[@]}";
      do
          echo "$i"
      done

}

array=("one" "two" "three")
copyFiles "${array[@]}"

• There need to be at least a space between function declaration and {

• You can not use $array, as array is an array not a variable. If you want to get all the values of an array use "$array[@]}"

• In you main function declaration you need arr="$@" as "${array[@]}" will expand to the indexed values separated by spaces, if you use $1 you would get only the first value. To get all the values use arr="$arr[@]}".

There are couple of problems. Here is the working form :

#!/bin/bash
function copyFiles {
   arr=( "$@" )
   for i in "${arr[@]}";
      do
          echo "$i"
      done

}

array=("one" "two" "three")
copyFiles "${array[@]}"

• There need to be at least a space between function declaration and {

• You can not use $array, as array is an array not a variable. If you want to get all the values of an array use "${array[@]}"

• In you main function declaration you need arr="$@" as "${array[@]}" will expand to the indexed values separated by spaces, if you use $1 you would get only the first value. To get all the values use arr="$arr[@]}".

There are couple of problems. Here is the working form :

#!/bin/bash
function copyFiles {
   arr="$@"
   for i in "${arr[@]}";
      do
          echo "$i"
      done

}

array=("one" "two" "three")
copyFiles "${array[@]}"

• There need to be at least a space between function declaration and {

• You can not use $array, as array is an array not a variable. If you want to get all the values of an array use "$array[@]}"

• In you main function declaration you need arr="$@" as "${array[@]}" will expand to the indexed values separated by spaces, if you use $1 you would get only the first value. To get all the values use arr="$arr[@]}".

There are couple of problems. Here is the working form :

#!/bin/bash
function copyFiles {
   arr=( "$@" )
   for i in "${arr[@]}";
      do
          echo "$i"
      done

}

array=("one" "two" "three")
copyFiles "${array[@]}"

• There need to be at least a space between function declaration and {

• You can not use $array, as array is an array not a variable. If you want to get all the values of an array use "$array[@]}"

• In you main function declaration you need arr="$@" as "${array[@]}" will expand to the indexed values separated by spaces, if you use $1 you would get only the first value. To get all the values use arr="$arr[@]}".