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1. If you only did test with the0xff-pattern, you would not be able to find this error. Sincebadblocksis not designed to erase the data, but to find bad blocks, multiple passes is not considered to be excessive.0xffand immediately checks if there is0xffwritten by reading the location from disk. So the stuck 0 is ruled out. Then, it does the same with0x00to rule out the stuck 1 error. so 1 pass with each pattern is sufficient. The other ones (alternating pattern of0and1) are against bits that stick together (if I set bit N to1, bit N+1 also goes to1as a result of the error)