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Rev

It's 172.16.0.0/16 :-). Also why 10.0.0.0 addresses because "there are more addresses available"? Do you think you'll ever reach the amount?
– sinni800
Commented Jun 20, 2011 at 16:52
3

@sinni - no, it is 172.16.0.0/12, as 172.31.255.255 marks the end of the range. /16 would end at 172.16.255.255. And I work on a larger network where it's convenient to assign pools for certain classes - so all printers are in 10.x.15.0, for example. All clients in one department are 10.2.0.0, another 10.3.0.0. The first department's printers are 10.2.15.0-10.2.15.255, the 2nd department's are 10.3.15.0. to 10.3.15.255. I'll never use all the addresses, but it's nice to have more blocks to assign out.
– Joel Coehoorn
Commented Jun 20, 2011 at 16:56
it's 172.16.0.0/16 because 16 to 32 are all their own subnetwork normally. So theres 16 nets in total in this range... I know what you mean, but I thought a little differently about it when you first said it. Subnetting it more than once makes sense :)
– sinni800
Commented Jun 20, 2011 at 17:00
The whole range is 172.16.0.0/12, but it is normally considered to be a block 16 /16s (172.16.0.0/16, 172.17.0.0/16, ..., 172.31.0.0/16) rather than one /12 in the same way 192.168.0.0/16 is usually considered to be 256 /24s and not one /16.
– David Spillett
Commented Jun 20, 2011 at 18:24

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