How can I convert a file with a lot hex numbers into the decimal?

Example: file1

 0x59999
 0x5acdc
 0xffeff

I want to start

$ cat file1 | util | cat >file2

and get file2 with smth like

 1021489
 1249230
 3458080

(numbers in example output are random, as I cant convert so long hex to dec)

Upd: perl : perl -pe '$_=hex;$_.="\n"'. Can anybody do it better?

The real task is a sorting of hex numbers.

How can I convert a file with a lot of hex numbers into decimal?

Example: file1

 0x59999
 0x5acdc
 0xffeff

I want to start

$ cat file1 | util | cat >file2

and get file2 with something like:

 1021489
 1249230
 3458080

(The numbers in example output are random, as I can't convert such long hex numbers to decimal)

UPDATE: I solved this with the following Perl command:

perl -pe '$_=hex;$_.="\n"'

Is there a better solution? The real task is needing to be able to sort hex numbers.

How can I convert a file with a lot hex numbers into the decimal?

Example: file1

 0x59999
 0x5acdc
 0xffeff

I want to start

$ cat file1 | util | cat >file2

and get file2 with smth like

 1021489
 1249230
 3458080

(numbers in output are random, as I can convert so long hex to dec)

Upd: perl : perl -pe '$_=hex;$_.="\n"'. Can anybody do it better?

The real task is a sorting of hex numbers.

How can I convert a file with a lot hex numbers into the decimal?

Example: file1

 0x59999
 0x5acdc
 0xffeff

I want to start

$ cat file1 | util | cat >file2

and get file2 with smth like

 1021489
 1249230
 3458080

(numbers in example output are random, as I cant convert so long hex to dec)

Upd: perl : perl -pe '$_=hex;$_.="\n"'. Can anybody do it better?

The real task is a sorting of hex numbers.