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It is the short way of representing a subnet mask.

As Steffen Opel points out in his answer, this is called CIDR notation and the number simply indicates the prefix size used to construct the subnet mask.

So /n means that the first n bits (out of 32 for IPv4) are set to 1, the rest are set to 0. To convert this to a decimal subnet mask you write it in to four octet's and convert to decimal.

So /24 produces 255.255.255.0 because you have twenty four 1 bits and then eigth 0 bits:

Binary:   11111111 11111111 11111111 00000000
Decimal:    255      255      255       0

The short value doesn't have to be a multiple of 8 (ie, it doesn't have to end of the octet boundaries), for example you can take /20 to get 255.255.240.0 as so:

Binary:   11111111 11111111 11110000 00000000
Decimal:    255      255      240       0

##Usage with IPv6 The same notation can be appiled to IPv6 as well. Since IPv6 uses 128 bits, instead of 32, the addresses are much larger. I won't go in to the full semantics here, because it's not relevant to the question, but will provide a quick example:

The subnet given in the question is represented by 192.168.15.0/24 and includes all the IPv4 addresses from 192.168.15.0 to 192.168.15.255

An IPv6 subnet can be represented in the same way, for example 2001:DB8::/48 contains all IPv6 addresses in the range 2001:DB8:0:0:0:0:0:0 to 2001:DB8:0:FFFF:FFFF:FFFF:FFFF:FFFF.

Note: IPv6 example shamelessly ripped from the Wikipedia CIDR article.


For more info on Subnet masks themselves, what they mean and how the are used, I would recommend you see the question What are the essentials of a Subnet mask?
Or look at the extensive answer to How does Subnetting Work?How does Subnetting Work? over at Server Fault.

It is the short way of representing a subnet mask.

As Steffen Opel points out in his answer, this is called CIDR notation and the number simply indicates the prefix size used to construct the subnet mask.

So /n means that the first n bits (out of 32 for IPv4) are set to 1, the rest are set to 0. To convert this to a decimal subnet mask you write it in to four octet's and convert to decimal.

So /24 produces 255.255.255.0 because you have twenty four 1 bits and then eigth 0 bits:

Binary:   11111111 11111111 11111111 00000000
Decimal:    255      255      255       0

The short value doesn't have to be a multiple of 8 (ie, it doesn't have to end of the octet boundaries), for example you can take /20 to get 255.255.240.0 as so:

Binary:   11111111 11111111 11110000 00000000
Decimal:    255      255      240       0

##Usage with IPv6 The same notation can be appiled to IPv6 as well. Since IPv6 uses 128 bits, instead of 32, the addresses are much larger. I won't go in to the full semantics here, because it's not relevant to the question, but will provide a quick example:

The subnet given in the question is represented by 192.168.15.0/24 and includes all the IPv4 addresses from 192.168.15.0 to 192.168.15.255

An IPv6 subnet can be represented in the same way, for example 2001:DB8::/48 contains all IPv6 addresses in the range 2001:DB8:0:0:0:0:0:0 to 2001:DB8:0:FFFF:FFFF:FFFF:FFFF:FFFF.

Note: IPv6 example shamelessly ripped from the Wikipedia CIDR article.


For more info on Subnet masks themselves, what they mean and how the are used, I would recommend you see the question What are the essentials of a Subnet mask?
Or look at the extensive answer to How does Subnetting Work? over at Server Fault.

It is the short way of representing a subnet mask.

As Steffen Opel points out in his answer, this is called CIDR notation and the number simply indicates the prefix size used to construct the subnet mask.

So /n means that the first n bits (out of 32 for IPv4) are set to 1, the rest are set to 0. To convert this to a decimal subnet mask you write it in to four octet's and convert to decimal.

So /24 produces 255.255.255.0 because you have twenty four 1 bits and then eigth 0 bits:

Binary:   11111111 11111111 11111111 00000000
Decimal:    255      255      255       0

The short value doesn't have to be a multiple of 8 (ie, it doesn't have to end of the octet boundaries), for example you can take /20 to get 255.255.240.0 as so:

Binary:   11111111 11111111 11110000 00000000
Decimal:    255      255      240       0

##Usage with IPv6 The same notation can be appiled to IPv6 as well. Since IPv6 uses 128 bits, instead of 32, the addresses are much larger. I won't go in to the full semantics here, because it's not relevant to the question, but will provide a quick example:

The subnet given in the question is represented by 192.168.15.0/24 and includes all the IPv4 addresses from 192.168.15.0 to 192.168.15.255

An IPv6 subnet can be represented in the same way, for example 2001:DB8::/48 contains all IPv6 addresses in the range 2001:DB8:0:0:0:0:0:0 to 2001:DB8:0:FFFF:FFFF:FFFF:FFFF:FFFF.

Note: IPv6 example shamelessly ripped from the Wikipedia CIDR article.


For more info on Subnet masks themselves, what they mean and how the are used, I would recommend you see the question What are the essentials of a Subnet mask?
Or look at the extensive answer to How does Subnetting Work? over at Server Fault.

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It is the short way of representing a subnet mask.

As Steffen Opel points out in his answeranswer, this is called CIDR notation and the number simply indicates the prefix size used to construct the subnet mask.

So /n means that the first n bits (out of 32 for IPv4) are set to 1, the rest are set to 0. To convert this to a decimal subnet mask you write it in to four octet's and convert to decimal.

So /24 produces 255.255.255.0 because you have twenty four 1 bits and then eigth 0 bits:

Binary:   11111111 11111111 11111111 00000000
Decimal:    255      255      255       0

The short value doesn't have to be a multiple of 8 (ie, it doesn't have to end of the octet boundaries), for example you can take /20 to get 255.255.240.0 as so:

Binary:   11111111 11111111 11110000 00000000
Decimal:    255      255      240       0

##Usage with IPv6 The same notation can be appiled to IPv6 as well. Since IPv6 uses 128 bits, instead of 32, the addresses are much larger. I won't go in to the full semantics here, because it's not relevant to the question, but will provide a quick example:

The subnet given in the question is represented by 192.168.15.0/24 and includes all the IPv4 addresses from 192.168.15.0 to 192.168.15.255

An IPv6 subnet can be represented in the same way, for example 2001:DB8::/48 contains all IPv6 addresses in the range 2001:DB8:0:0:0:0:0:0 to 2001:DB8:0:FFFF:FFFF:FFFF:FFFF:FFFF.

Note: IPv6 example shamelessly ripped from the Wikipedia CIDR article.


For more info on Subnet masks themselves, what they mean and how the are used, I would recommend you see the question What are the essentials of a Subnet mask?What are the essentials of a Subnet mask?
Or look at the extensive answer to How does Subnetting Work? over at Server Fault.

It is the short way of representing a subnet mask.

As Steffen Opel points out in his answer, this is called CIDR notation and the number simply indicates the prefix size used to construct the subnet mask.

So /n means that the first n bits (out of 32 for IPv4) are set to 1, the rest are set to 0. To convert this to a decimal subnet mask you write it in to four octet's and convert to decimal.

So /24 produces 255.255.255.0 because you have twenty four 1 bits and then eigth 0 bits:

Binary:   11111111 11111111 11111111 00000000
Decimal:    255      255      255       0

The short value doesn't have to be a multiple of 8 (ie, it doesn't have to end of the octet boundaries), for example you can take /20 to get 255.255.240.0 as so:

Binary:   11111111 11111111 11110000 00000000
Decimal:    255      255      240       0

##Usage with IPv6 The same notation can be appiled to IPv6 as well. Since IPv6 uses 128 bits, instead of 32, the addresses are much larger. I won't go in to the full semantics here, because it's not relevant to the question, but will provide a quick example:

The subnet given in the question is represented by 192.168.15.0/24 and includes all the IPv4 addresses from 192.168.15.0 to 192.168.15.255

An IPv6 subnet can be represented in the same way, for example 2001:DB8::/48 contains all IPv6 addresses in the range 2001:DB8:0:0:0:0:0:0 to 2001:DB8:0:FFFF:FFFF:FFFF:FFFF:FFFF.

Note: IPv6 example shamelessly ripped from the Wikipedia CIDR article.


For more info on Subnet masks themselves, what they mean and how the are used, I would recommend you see the question What are the essentials of a Subnet mask?
Or look at the extensive answer to How does Subnetting Work? over at Server Fault.

It is the short way of representing a subnet mask.

As Steffen Opel points out in his answer, this is called CIDR notation and the number simply indicates the prefix size used to construct the subnet mask.

So /n means that the first n bits (out of 32 for IPv4) are set to 1, the rest are set to 0. To convert this to a decimal subnet mask you write it in to four octet's and convert to decimal.

So /24 produces 255.255.255.0 because you have twenty four 1 bits and then eigth 0 bits:

Binary:   11111111 11111111 11111111 00000000
Decimal:    255      255      255       0

The short value doesn't have to be a multiple of 8 (ie, it doesn't have to end of the octet boundaries), for example you can take /20 to get 255.255.240.0 as so:

Binary:   11111111 11111111 11110000 00000000
Decimal:    255      255      240       0

##Usage with IPv6 The same notation can be appiled to IPv6 as well. Since IPv6 uses 128 bits, instead of 32, the addresses are much larger. I won't go in to the full semantics here, because it's not relevant to the question, but will provide a quick example:

The subnet given in the question is represented by 192.168.15.0/24 and includes all the IPv4 addresses from 192.168.15.0 to 192.168.15.255

An IPv6 subnet can be represented in the same way, for example 2001:DB8::/48 contains all IPv6 addresses in the range 2001:DB8:0:0:0:0:0:0 to 2001:DB8:0:FFFF:FFFF:FFFF:FFFF:FFFF.

Note: IPv6 example shamelessly ripped from the Wikipedia CIDR article.


For more info on Subnet masks themselves, what they mean and how the are used, I would recommend you see the question What are the essentials of a Subnet mask?
Or look at the extensive answer to How does Subnetting Work? over at Server Fault.

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It is the short way of representing a subnet mask.

As Steffen Opel points out in his answer, this is called CIDR notation and the number simply indicates the prefix size used to construct the subnet mask.

So /n means that the first n bits (out of 32 for IPv4) are set to 11, the rest are set to 0. To convert this to a decimal subnet mask you write it in to four octet's and convert to decimal.

So /24 produces 255.255.255.0 because you have twenty four 1 bits and then eigth 0 bits:

Binary:   11111111 11111111 11111111 00000000
Decimal:    255      255      255       0

The short value doesn't have to be a multiple of 8 (ie, it doesn't have to end of the octet boundaries), for example you can take /20 to get 255.255.240.0 as so:

Binary:   11111111 11111111 11110000 00000000
Decimal:    255      255      240       0

##Usage with IPv6 The same notation can be appiled to IPv6 as well. Since IPv6 uses 128 bits, instead of 32, the addresses are much larger. I won't go in to the full semantics here, because it's not relevant to the question, but will provide a quick example:

The subnet given in the question is represented by 192.168.15.0/24 and includes all the IPv4 addresses from 192.168.15.0 to 192.168.15.255

An IPv6 subnet can be represented in the same way, for example 2001:DB8::/48 contains all IPv6 addresses in the range 2001:DB8:0:0:0:0:0:0 to 2001:DB8:0:FFFF:FFFF:FFFF:FFFF:FFFF.

Note: IPv6 example shamelessly ripped from the Wikipedia CIDR article.


For more info on Subnet masks themselves, what they mean and how the are used, I would recommend you see the question What are the essentials of a Subnet mask?
Or look at the extensiveextensive answer to How does Subnetting Work? over at Server Fault.

It is the short way of representing a subnet mask.

/n means that the first n bits (out of 32) are set to 1. So /24 produces 255.255.255.0.

For more info on Subnet masks see the question What are the essentials of a Subnet mask?
Or look at the extensive answer to How does Subnetting Work? over at Server Fault.

It is the short way of representing a subnet mask.

As Steffen Opel points out in his answer, this is called CIDR notation and the number simply indicates the prefix size used to construct the subnet mask.

So /n means that the first n bits (out of 32 for IPv4) are set to 1, the rest are set to 0. To convert this to a decimal subnet mask you write it in to four octet's and convert to decimal.

So /24 produces 255.255.255.0 because you have twenty four 1 bits and then eigth 0 bits:

Binary:   11111111 11111111 11111111 00000000
Decimal:    255      255      255       0

The short value doesn't have to be a multiple of 8 (ie, it doesn't have to end of the octet boundaries), for example you can take /20 to get 255.255.240.0 as so:

Binary:   11111111 11111111 11110000 00000000
Decimal:    255      255      240       0

##Usage with IPv6 The same notation can be appiled to IPv6 as well. Since IPv6 uses 128 bits, instead of 32, the addresses are much larger. I won't go in to the full semantics here, because it's not relevant to the question, but will provide a quick example:

The subnet given in the question is represented by 192.168.15.0/24 and includes all the IPv4 addresses from 192.168.15.0 to 192.168.15.255

An IPv6 subnet can be represented in the same way, for example 2001:DB8::/48 contains all IPv6 addresses in the range 2001:DB8:0:0:0:0:0:0 to 2001:DB8:0:FFFF:FFFF:FFFF:FFFF:FFFF.

Note: IPv6 example shamelessly ripped from the Wikipedia CIDR article.


For more info on Subnet masks themselves, what they mean and how the are used, I would recommend you see the question What are the essentials of a Subnet mask?
Or look at the extensive answer to How does Subnetting Work? over at Server Fault.

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DMA57361
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