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Rev

1

Good answer, but shouldn't the power values in the last two paragraphs be 0.45W and then 0.8W? Regardless, the point is that P=I^2R, so increasing I significantly increases P (the waste power dissipation).
– sblair
Commented Feb 25, 2010 at 0:52
Good catch - I incorrectly used 10A to calculate the power (typo). P=I^2R is an elegant way to summarize it!
– Fred Hamilton
Commented Feb 25, 2010 at 1:05
2

Nice answer. +1 for actually calculating stuff, and explaining the calculations.
– sleske
Commented Feb 25, 2010 at 1:39
Very nice answer, shame you couldn't have got it answered a bit quicker
– Earlz
Commented Feb 25, 2010 at 16:55
1

This should be the accepted answer. Although the accepted one contains valuable information, the question was specifically about, quote, "What happens to a PSU in a brownout to damage it", not what happens to motherboard. So this is the right answer for this specific question. You saved me from distroying a printer PSU, because I was going to modify it to work with 110VAC instead of the rated 220VAC
– Abraham Toledo
Commented Jun 15, 2018 at 14:32

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Correct minor typos or mistakes
Clarify meaning without changing it
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Always respect the author’s intent
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create code fences with backticks ` or tildes ~
```
like so
```
add language identifier to highlight code
```python
def function(foo):
print(foo)
```
put returns between paragraphs
for linebreak add 2 spaces at end
_italic_ or **bold**
indent code by 4 spaces
backtick escapes `like _so_`
quote by placing > at start of line
to make links (use https whenever possible)
<https://example.com>
[example](https://example.com)
<a href="https://example.com">example</a>

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