I'd like to setup my laptop where one HDD has two copies of Windows 7, one encrypted and the other unencrypted. The VeraCrypt bootloader will say "Press ESC To Boot;" entering the correct password should boot the encrypted OS, and pressing ESC should boot the unencrypted.

Although I've found this situation mentioned in many places, I've only been able to achieve this behavior by installing each copy of Windows on its own separate HDD; no matter what I try, it doesn't seem to work on one HDD.

Let's start by laying out the disk like this:

Partition 0) Win7 System Partition (100mb)
Partition 1) Encrypted Win7
Partition 2) Unencrypted Win7

Initially, everything is unencrypted. We then go through the VC Encrypt System Partition/Drive wizard to encrypt Partition 1. After it completes, the situation is:

• If you set Partition 0 as Active: Whether you enter the password or press ESC at the VC bootloader, you're subsequently presented by the Windows boot menu, where you need to select between the two OSs. If you pressed ESC, only the unencrypted one will work, otherwise either will work.
• If you set Partition 1 as Active: Entering the VC password will boot the encrypted OS, but pressing ESC says "no bootable partition found."
• If you set Partition 2 as Active: Whether you press ESC or enter the password, it always boots the unencrypted OS.

These 3 behaviors are logical, I just can't figure out how to actually achieve the behavior I'm after. My expectation was that there'd be a way for the VeraCrypt Boot Manager (which is what's invoked after you press ESC) to select between OSs installed on the other partitions, yet it seems to ignore anything that isn't the Active partition.

Note that even the VeraCrypt wizard itself makes it sound like what I'm trying to do should be possible (see here: "...you will only need to press the Esc key to start the unencrypted system (if there are multiple unencrypted systems, you will also need to choose which system to start in the VeraCrypt boot manager menu.)").

This answer also makes it sound like it should be possible. Is there perhaps something I'm doing wrong, some reason why the VC bootloader won't find any of the other bootable partitions on the drive - just the Active one?

I'd like to setup my laptop where one HDD has two copies of Windows 7, one encrypted and the other unencrypted. The VeraCrypt bootloader will say "Press ESC To Boot;" entering the correct password should boot the encrypted OS, and pressing ESC should boot the unencrypted.

Although I've found this situation mentioned in many places, I've only been able to achieve this behavior by installing each copy of Windows on its own separate HDD; no matter what I try, it doesn't seem to work on one HDD.

Let's start by laying out the disk like this:

Partition 0) Win7 System Partition (100mb)
Partition 1) Encrypted Win7
Partition 2) Unencrypted Win7

Initially, everything is unencrypted. We then go through the VC Encrypt System Partition/Drive wizard to encrypt Partition 1. After it completes, the situation is:

• If you set Partition 0 as Active: Whether you enter the password or press ESC at the VC bootloader, you're subsequently presented by the Windows boot menu, where you need to select between the two OSs. If you pressed ESC, only the unencrypted one will work, otherwise either will work.
• If you set Partition 1 as Active: Entering the VC password will boot the encrypted OS, but pressing ESC says "no bootable partition found."
• If you set Partition 2 as Active: Whether you press ESC or enter the password, it always boots the unencrypted OS.

These 3 behaviors are logical, I just can't figure out how to actually achieve the behavior I'm after. My expectation was that there'd be a way for the VeraCrypt Boot Manager (which is what's invoked after you press ESC) to select between OSs installed on the other partitions, yet it seems to ignore anything that isn't the Active partition.

Note that even the VeraCrypt wizard itself makes it sound like what I'm trying to do should be possible (see here: "...you will only need to press the Esc key to start the unencrypted system (if there are multiple unencrypted systems, you will also need to choose which system to start in the VeraCrypt boot manager menu.)").

This answer also makes it sound like it should be possible. Is there perhaps something I'm doing wrong, some reason why the VC bootloader won't find any of the other bootable partitions on the drive - just the Active one?

I'd like to setup my laptop where one internal HDD has two copies of Windows 7, one encrypted and the other unencrypted. The VeraCrypt bootloader will say "Press ESC To Boot;" entering the correct password should boot the encrypted OS, and pressing ESC should boot the unencrypted.

Although I've found this situation mentioned in many places, I've only been able to achieve this behavior by installing each copy of Windows on its own separate HDD; no matter what I try, it doesn't seem to work on one HDD.

Let's start by laying out the disk like this:

Partition 0) Win7 System Partition (100mb)
Partition 1) Encrypted Win7
Partition 2) Unencrypted Win7

Initially, everything is unencrypted. We then go through the VC Encrypt System Partition/Drive wizard to encrypt Partition 1. After it completes, the situation is:

• If you set Partition 0 as Active: Whether you enter the password or press ESC at the VC bootloader, you're subsequently presented by the Windows boot menu, where you need to select between the two OSs. If you pressed ESC, only the unencrypted one will work, otherwise either will work.
• If you set Partition 1 as Active: Entering the VC password will boot the encrypted OS, but pressing ESC says "no bootable partition found."
• If you set Partition 2 as Active: Whether you press ESC or enter the password, it always boots the unencrypted OS.

These 3 behaviors are logical, I just can't figure out how to actually achieve the behavior I'm after. My expectation was that there'd be a way for the VeraCrypt Boot Manager (which is what's invoked after you press ESC) to select between OSs installed on the other partitions, yet it seems to ignore anything that isn't the Active partition.

Note that even the VeraCrypt wizard itself makes it sound like what I'm trying to do should be possible (see here: "...you will only need to press the Esc key to start the unencrypted system (if there are multiple unencrypted systems, you will also need to choose which system to start in the VeraCrypt boot manager menu.)").

This answer also makes it sound like it should be possible. Is there perhaps something I'm doing wrong, some reason why the VC bootloader won't find any of the other bootable partitions on the drive - just the Active one?

I'd like to setup my laptop where one HDD has two copies of Windows 7, one encrypted and the other unencrypted. The VeraCrypt bootloader will say "Press ESC To Boot;" entering the correct password should boot the encrypted OS, and pressing ESC should boot the unencrypted.

Although I've found this situation mentioned in many places, I've only been able to achieve this behavior by installing each copy of Windows on its own separate HDD; no matter what I try, it doesn't seem to work on one HDD.

Let's start by laying out the disk like this:

Partition 0) Win7 System Partition (100mb)
Partition 1) Encrypted Win7
Partition 2) Unencrypted Win7

Initially, everything is unencrypted. We then go through the VC Encrypt System Partition/Drive wizard to encrypt Partition 1. After it completes, the situation is:

• If you set Partition 0 as Active: Whether you enter the password or press ESC at the VC bootloader, you're subsequently presented by the Windows boot menu, where you need to select between the two OSs. If you pressed ESC, only the unencrypted one will work, otherwise either will work.
• If you set Partition 1 as Active: Entering the VC password will boot the encrypted OS, but pressing ESC says "no bootable partition found."
• If you set Partition 2 as Active: Whether you press ESC or enter the password, it always boots the unencrypted OS.

These 3 behaviors are logical, I just can't figure out how to actually achieve the behavior I'm after. My expectation was that there'd be a way for the VeraCrypt Boot Manager (which is what's invoked after you press ESC) to select between OSs installed on the other partitions, yet it seems to ignore anything that isn't the Active partition.

Note that even the VeraCrypt wizard itself makes it sound like what I'm trying to do should be possible (see here: "...you will only need to press the Esc key to start the unencrypted system (if there are multiple unencrypted systems, you will also need to choose which system to start in the VeraCrypt boot manager menu.)").

This answer also makes it sound like it should be possible. Is there perhaps something I'm doing wrong, some reason why the VC bootloader won't find any of the other bootable partitions on the drive - just the Active one?

I'd like to setup my laptop where one internal HDD has two copies of Windows 7, one encrypted and the other unencrypted. The VeraCrypt bootloader will say "Press ESC To Boot;" entering the correct password should boot the encrypted OS, and pressing ESC should boot the unencrypted.

Although I've found this situation mentioned in many places, I've only been able to achieve this behavior by installing each copy of Windows on its own separate HDD; no matter what I try, it doesn't seem to work on one HDD.

Let's start by laying out the disk like this:

Partition 0) Win7 System Partition (100mb)
Partition 1) Encrypted Win7
Partition 2) Unencrypted Win7

Initially, everything is unencrypted. We then go through the VC Encrypt System Partition/Drive wizard to encrypt Partition 1. Now we're at a situation where:

• If you set Partition 0 as Active: Whether you enter the password or press ESC at the VC bootloader, you're subsequently presented by the Windows boot menu, where you need to select between the two OSs. If you pressed ESC, only the unencrypted one will work, otherwise either will work.
• If you set Partition 1 as Active: Entering the VC password will boot the encrypted OS, but pressing ESC says "no bootable partition found."
• If you set Partition 2 as Active: Whether you press ESC or enter the password, it always boots the unencrypted OS.

These 3 behaviors are logical, I just can't figure out how to actually achieve the behavior I'm after. My expectation was that there'd be a way for the VeraCrypt Boot Manager (which is what's invoked after you press ESC) to select between OSs installed on the other partitions, yet it seems to ignore anything that isn't the Active partition.

Note that even the VeraCrypt wizard itself makes it sound like what I'm trying to do should be possible (see here: "...you will only need to press the Esc key to start the unencrypted system (if there are multiple unencrypted systems, you will also need to choose which system to start in the VeraCrypt boot manager menu.)").

This answer also makes it sound like it should be possible. Is there perhaps something I'm doing wrong, some reason why the VC bootloader won't find any of the other bootable partitions on the drive - just the Active one?

I'd like to setup my laptop where one internal HDD has two copies of Windows 7, one encrypted and the other unencrypted. The VeraCrypt bootloader will say "Press ESC To Boot;" entering the correct password should boot the encrypted OS, and pressing ESC should boot the unencrypted.

Although I've found this situation mentioned in many places, I've only been able to achieve this behavior by installing each copy of Windows on its own separate HDD; no matter what I try, it doesn't seem to work on one HDD.

Let's start by laying out the disk like this:

Partition 0) Win7 System Partition (100mb)
Partition 1) Encrypted Win7
Partition 2) Unencrypted Win7

Initially, everything is unencrypted. We then go through the VC Encrypt System Partition/Drive wizard to encrypt Partition 1. After it completes, the situation is:

• If you set Partition 0 as Active: Whether you enter the password or press ESC at the VC bootloader, you're subsequently presented by the Windows boot menu, where you need to select between the two OSs. If you pressed ESC, only the unencrypted one will work, otherwise either will work.
• If you set Partition 1 as Active: Entering the VC password will boot the encrypted OS, but pressing ESC says "no bootable partition found."
• If you set Partition 2 as Active: Whether you press ESC or enter the password, it always boots the unencrypted OS.

These 3 behaviors are logical, I just can't figure out how to actually achieve the behavior I'm after. My expectation was that there'd be a way for the VeraCrypt Boot Manager (which is what's invoked after you press ESC) to select between OSs installed on the other partitions, yet it seems to ignore anything that isn't the Active partition.

Note that even the VeraCrypt wizard itself makes it sound like what I'm trying to do should be possible (see here: "...you will only need to press the Esc key to start the unencrypted system (if there are multiple unencrypted systems, you will also need to choose which system to start in the VeraCrypt boot manager menu.)").

This answer also makes it sound like it should be possible. Is there perhaps something I'm doing wrong, some reason why the VC bootloader won't find any of the other bootable partitions on the drive - just the Active one?